Electrostatics Question 691
Two particles of equal mass m and charge q are placed at a distance of 16 cm. They do not experience any force. The value of $ \frac{q}{m} $ is
Options:
1
B) $ \sqrt{\frac{\pi {\varepsilon _{0}}}{G}} $
C) $ \sqrt{\frac{G}{4\pi {\varepsilon _{0}}}} $
D) $ \sqrt{4\pi {\varepsilon _{0}}} $
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Answer:
Correct Answer: D
Solution:
They will not experience any force if they are in motion at constant velocity in an inertial frame of reference.
$ |{{\vec{F}} _{G}}|=|{{\vec{F}} _{e}}| $
$ \Rightarrow G\frac{m^{2}}{{{( 16\times {{10}^{-2}} )}^{2}}}=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{q^{2}}{{{( 16\times {{10}^{-2}} )}^{2}}} $
$ \Rightarrow \frac{q}{m}=\sqrt{\frac{4\pi {\varepsilon _{0}}}{G}} $
BETA
