Electrostatics Question 703
Question: ABC is an equilateral triangle. Charges +q are placed at each corner as shown in fig. The electric intensity at center O will be
Options:
A) $ \frac{1}{4\pi {\in _{0}}}\frac{q}{r} $
B) $ \frac{1}{4\pi {\in _{0}}}\frac{q}{r^{2}} $
C) $ \frac{1}{4\pi {\in _{0}}}\frac{3q}{r^{2}} $
D) Zero
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Unit positive charge at 0 will be repelled equally by three charges at the three corners of triangle. By symmetry, relsultant
$ \vec{E} $ at O would be zero.
BETA
