Electrostatics Question 723
The electric field intensity at the center of a uniformly charged hemispherical shell is $ E _{0}. $ Now two portions of the remaining portion are shown in Fig. If $ \alpha =\beta =\pi /3 $ , then the electric field intensity at the center due to the remaining portion is
Options:
A) $ E _{0}/3 $
B) $ E _{0}/6 $
C) $ E _{0}/2 $
D) Information incomplete
Show Answer
Answer:
Correct Answer: C
Solution:
[c] The magnitude of electric field intensity due to each part of the hemispherical surface at the center ?O? is same. Suppose it is E. $ E+\frac{E}{2}+\frac{E}{2}=E _{0} $ or $ 2E=E _{0}\text{ or }E=\frac{E _{0}}{2} $
BETA
