Electrostatics Question 241

The electric field in a region is radially outward with magnitude $ E=A/r $ . The charge contained in a sphere of radius $ r $ centered at the origin is [AMU 1999]

Options:

A) $ 1.77mm $

B) $ 3.51mm $

C) $ 1.77cm $

D) $ 3.51cm $

Show Answer

Answer:

Correct Answer: A

Solution:

Let an electron be projected towards the plate from a distance r as shown in fig.

It will not strike the plate if and only if KE ≤ e(E×r) (where E = Electric field due to charge plate $ =\frac{\sigma }{2{\varepsilon _{0}}} $ ) therefore $ r\ge \frac{KE}{eE} $ .

Hence minimum value of r is given by $ r=\frac{KE}{eE}=\frac{200eV}{e\times \frac{2{\varepsilon _{0}}}{\sigma}} $

$ =\frac{400\times 8.86\times {{10}^{-12}}}{2\times {{10}^{-6}}}=1.77\times {{10}^{-3}}m $



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