Electrostatics Question 732
Consider an electric field $ \vec{E}=E _{0}\hat{x} $ where $ E _{0} $ is a constant. The flux through the shaded area is
Options:
A) $ 2E _{0}a^{2} $
B) $ \sqrt{2}E _{0}a^{2} $
C) $ E _{0}a^{2} $
D) $ \frac{E _{0}a^{2}}{\sqrt{2}} $
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Answer:
Correct Answer: C
Solution:
$ \int {{}}^{{}}{\vec{E}.\overrightarrow{dA}=\frac{Q{enc}}{\epsilon_0} } $
$ \Rightarrow \phi =E _{0}(a\times a\sqrt{2})\cos 45{}^\circ -E _{0}a^{2}\sqrt{2} $