Electrostatics Question 743
For a given surface the Gauss’s law is stated as $ \int _{\vec{E} \cdot d\vec{A}} = 0 $ From this we can conclude that
Options:
A) E is necessarily zero on the surface
B) E is perpendicular to the surface at every point
C) the total flux through the surface is zero
D) the flux is only going out of the surface, not into it
Show Answer
Answer:
Correct Answer: C
Solution:
$ \int _{\vec{E} \cdot d\vec{A}}=0, $
represents charge inside a closed surface is zero. Electric field at any point on the surface may be zero.
BETA
