Electrostatics Question 242
Charge $ q $ is uniformly distributed over a thin half ring of radius $ R $ . The electric field at the centre of the ring is [Roorkee 1999]
Options:
A) $ 6.0\times 10^{27} \text{C}$
B) $ 2.67\times 10^{7}C $
C) $ 6\times 10^{23}C $
D) $ 1.67\times 10^{23} \text{mol}^{-1}$
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Answer:
Correct Answer: B
Solution:
$ Q=ne $ ;
where n = number of moles $ ~\times \text{6}.0\text{2}\times \text{1}{{0}^{\text{23}}}\times \text{1}{{0}^{1}} $
therefore $ Q=\frac{500}{18}\times 6.02\times 10^{23}\times 10\times 1.6\times {{10}^{-19}}=2.67\times 10^{7} $
BETA
