Electrostatics Question 25
Question: The radius of two metallic spheres $ A $ and $ B $ are $ r _{1} $ and $ r _{2} $ respectively $ (r _{1}>r _{2}) $ . They are connected by a thin wire and the system is given a certain charge. The charge will be greater
Options:
A) On the surface of the sphere $ B $
B) On the surface of the sphere $ A $
C) Equal on both
D) Zero on both
Show Answer
Answer:
Correct Answer: B
Solution:
After connection of wire, potential becomes equal $ \frac{Q _{1}}{r _{1}}=\frac{Q _{2}}{r _{2}} $
therefore $ \frac{Q _{1}}{Q _{2}}=\frac{r _{1}}{r _{2}} $ when r1 > r2, then $ Q _{1}>Q _{2} $
BETA
