Electrostatics Question 814
Question: A capacitor of capacity $ C _{1} $ is charged up to V volt and then connected to an uncharged capacitor of capacity $ C _{2}. $ Then final potential difference across each will be
Options:
A) $ \frac{C _{2}V}{C _{1}+C _{2}} $
B) $ ( 1+\frac{C _{2}}{C _{1}} )V $
C) $ \frac{C _{1}V}{C _{1}+C _{2}} $
D) $ ( 1-\frac{C _{2}}{C _{1}} )V $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Common potential $ V=\frac{C _{1}V+C _{2}\times 0}{C _{1}+C _{2}} $
$ =\frac{C _{1}}{C _{1}+C _{2}}V $
BETA
