Electrostatics Question 92
Question: A parallel plate air capacitor is charged to a potential difference of V. After disconnecting the battery, distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates [KCET 1999]
Options:
A) Decreases
B) Increases
C) Becomes zero
D) Does not change
Show Answer
Answer:
Correct Answer: B
Solution:
$ V=\frac{Q}{C} $ =$ \frac{Qd}{{\varepsilon _{0}}KA} $
therefore $ V\propto d $
BETA
