Electrostatics Question 263
A parallel plate air capacitor has a capacitance of $ 100\mu F $ . The plates are at a distance $ d $ apart. If a slab of thickness $ t(t\le d) $ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be [MP PMT 2003]
Options:
A) $ +,-,+,-,-,+ $
B) $ +,-,+,-,+,- $
C) $ +,+,-,+,-,- $
D) $ -,+,+,-,+,- $
Show Answer
Answer:
Correct Answer: D
Solution:
If the charges are arranged according to the option D, the electric fields due to P and S and due to Q and T add to zero, while due to U and R add up.
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