Em Waves Question 77
Question: An electron is accelerated through a potential difference of V volt. It has a wavelength $ \lambda $ associated with it. Through what potential difference an electron must be accelerated so that its de Broglie wavelength is the same as that of a Proton? Take mass of proton to be 1837 times larger than the mass of electron.
Options:
A) $ Vvolt $
B) $ 1837V,volt $
C) $ V/1837,volt $
D) $ \sqrt{1837}V,volt $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ \lambda =\frac{h}{\sqrt{2mqV}},mV=\text{constant} $
$ 1837V’=1\times V $ or $ V’=\frac{V}{1837} $ volt
BETA
