Em Waves Question 84
Question: The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000 $ \overset{\text{o}}{\mathop{\text{A}}}, $ falls on it. The potential difference applied to stop! The fastest photoelectrons is $ [ h=4.14\times {{10}^{-15}}eVs ] $
Options:
A) 1.2 V
B) 2.24 V
C) 3.6 V
D) 4.8 V
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ eV=hv-{\phi _{0}}=( \frac{12375}{2000}-5.01 )eV $
$ V=(6.1875-5.01)V=1.18V\approx 1.2V $
BETA
