Em Waves Question 145
Question: A charged particle oscillates about its mean equilibrium position with a frequency of $ 10^{9}Hz $ .
The electromagnetic waves produced
Options:
A) will have frequency of $ 10^{6}Hz $
B) will have frequency of $ 2\times 10^{3}\ Hz $
C) will have wavelength of 0.3 m
D) fall in the region of U.V. waves
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Answer:
Correct Answer: C
Solution:
[c] The frequency of the charged particles oscillates about its mean equilibrium position $ =10^{9}Hz $ . Vibrating particle produces electric and magnetic field. So, frequency of electromagnetic waves produced by the charged particle is $ v=10^{9}Hz $ . Wavelength $ \lambda =\frac{c}{v}=\frac{3\times 10^{8}}{10^{9}}=0.3m $ Since the range of radio waves is between 10 Hz to $ 10^{12}Hz $ and hence $ 10^{9}Hz $ lies in region of radio waves.
BETA
