Fluid Mechanics Viscosity Question 100
There is a hole in the bottom of tank having water. If total pressure at bottom is 3 atm (1 atm = 10^5 N/m2) then the velocity of water flowing from hole is[CPMT 2002]
Options:
A)$ \sqrt{400},m/s $
B)$ \sqrt{600,},m/s $
C)$ \sqrt{60},m/s $
D)None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Pressure at the bottom of tank $ P=h\rho g=3\times 10^{5}\frac{N}{m^{2}} $ Pressure due to liquid column Pl= $ 3\times 10^{5}-1\times 10^{5}=2\times 10^{5} $ and velocity of water $ v=\sqrt{2gh} $ $ \therefore \ v=\sqrt{\frac{2P_{l}}{\rho }}=\sqrt{\frac{2\times 2\times 10^{5}}{10^{3}}}=\sqrt{400},m/s $
BETA
