Fluid Mechanics Viscosity Question 114
A sniper fires a rifle bullet into a gasoline tank making a hole 53.0 m below the surface of gasoline. The tank was sealed at 3.10 atm. The stored gasoline has a density of 660 kg/m³. The velocity with which gasoline begins to shoot out of the hole is
Options:
A) The volume of the liquid flowing through the tube in unit time is $ A_{1}v_{1} $
B) $ v_{2}-v_{1}=\sqrt{2gh} $
C) $ v_{2}^{2}-v_{1}^{2}=2g\Delta h $
D)The energy per unit mass of the liquid is the same in both sections of the tube
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Answer:
Correct Answer: C
Solution:
According to Bernoulli’s theorem, $ P_{1}+\frac{1}{2}\rho v_{1}^{2}=P_{2}+\frac{1}{2}\rho v_{2}^{2} $ Þ $ P_{1}-P_{2}=\frac{1}{2}\rho \left( v_{2}^{2}-v_{1}^{2} \right) $ Þ $ (P_{1}-P_{2})=\rho g h=\frac{1}{2}\rho \left( v_{2}^{2}-v_{1}^{2} \right) $ \ $ v_{2}^{2}-v_{1}^{2}=2gh $ Hence option (c) is correct.
BETA
