Fluid Mechanics Viscosity Question 126

Question: When a body falls in air, the resistance of air depends to a great extent on the shape of the body, 3 different shapes are given. Identify the combination of air resistances which truly represents the physical situation. (The cross sectional areas are the same). [KCET 2005]

Options:

A)$ \frac{8}{9}X $

B)$ \frac{9}{8}X $

C)$ \frac{5}{7}X $

D)$ \frac{7}{5}X $

Show Answer

Answer:

Correct Answer: A

Solution:

Fluid resistance is given by $ R=\frac{8\eta l}{\pi r^{4}}. $ When two capillary tubes of same size are joined in parallel, then equivalent fluid resistance is$ R_{e}=R_{1}+R_{2}=\frac{8\eta L}{\pi r^{4}}+\frac{8\eta L}{\pi (2r)^{4}}=\left( \frac{8\eta L}{\pi r^{4}} \right)\times \frac{17}{16} $ Equivalent resistance becomes $ \frac{17}{16} $ times so rate of flow will be $ \frac{16}{17}X $



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