Fluid Mechanics Viscosity Question 189
Question: The fraction of a floating object of volume $ V_{0} $ and density $ d_{0} $ above the surface of a liquid of density d will be
Options:
A)$ \frac{d_{0}}{d} $
B)$ \frac{dd_{0}}{d+d_{0}} $
C)$ \frac{d-d_{0}}{d} $ $ $
D)$ \frac{dd_{0}}{d-d_{0}} $
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Answer:
Correct Answer: C
Solution:
For the floatation $ V_{0}d_{0}g=V_{in}\ d\ g $ Þ$ V_{in}=V_{0}\frac{d_{0}}{d} $ $ V_{out}=V_{0}-V_{in}=V_{0}-V_{0}\frac{d_{0}}{d} $ $ =V_{0}\left[ \frac{d-d_{0}}{d} \right] $ Þ $ \frac{V_{out}}{V_{0}}=\frac{d-d_{0}}{d}. $
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