Fluid Mechanics Viscosity Question 210
Question: The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is[AMU 1995]
Options:
A)5 m
B)10 m
C)15 m
D)20 m
Show Answer
Answer:
Correct Answer: C
Solution:
$ P_{1}V_{1}=P_{2}V_{2} $ Þ $ (P_{0}+h\rho g)V $ =$ P_{0}\times \frac{4}{3}\pi {{(2r)}^{3}} $ Þ $ h\rho g=2P_{0} $ Þ $ h=\frac{2\times 75\times 13.6\times g}{\frac{13.6}{10}\times g} $ = 15 m
BETA
