Fluid Mechanics Viscosity Question 237
Question: The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is [AMU 1995]
Options:
A) 5 m
B)10 m
C) 15 m
D)20 m
Show Answer
Answer:
Correct Answer: C
Solution:
$ P_{1}V_{1}=P_{2}V_{2} $ Þ $ (H_{Hg}{\rho_{Hg}}+H_{W}{\rho_{W}})V=H_{Hg}{\rho_{Hg}}\times 3V $ Þ $ H_{Hg}{\rho_{Hg}}+H_{W}\frac{{\rho_{Hg}}}{10}=3H_{Hg}{\rho_{Hg}} $ Þ$ H_{W}=2H_{Hg}\times 10 $ $ =\frac{2\times 75\times 10}{100}=15m $
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