Fluid Mechanics Viscosity Question 261

Question: An iceberg is floating in ocean. What fraction of its volume is above the water? (Given: density of ice$ =900kg/m^{3} $ and density of ocean water $ =1030kg/m^{3} $ )

Options:

A) $ \frac{90}{103} $

B) $ \frac{13}{103} $

C) $ \frac{10}{103} $

D) $ \frac{1}{103} $

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Answer:

Correct Answer: B

Solution:

[b] Let V be the volume of iceberg and let x be the fraction of volume above water. Using law of floatation, weight of floating body= weight of liquid displaced by part of the floating body inside the liquid. Therefore, $ V{\rho_{ice}}g=(1-x)V{\rho_{water}}g. $ Using the value of$ {\rho_{ice}},and,{\rho_{water}} $ , we get$ x=(13/103) $ .