Fluid Mechanics Viscosity Question 264
Question: The two thigh bones, each of cross-sectional area $ 10cm^{2} $ support the upper part of a human body of mass 40 kg. Estimate the average pressure sustained by the bones. Take $ g=10m/s^{2} $
Options:
A) $ 2\times 10^{5}N/m^{2} $
B) $ 5\times 10^{4}N/m^{2} $
C) $ 2\times 10^{7}N/m^{2} $
D) $ 3\times 10^{6}N/m^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Total cross-sectional area of the thigh bones $ A=2(10\times {{10}^{-4}})=2\times {{10}^{-3}}m^{2} $ Force acting on the bones $ =mg=40\times 10 $ $ =400N $ b $ \therefore ,,P_{av}=\frac{F}{A}=\frac{400}{2\times {{10}^{-3}}}=2\times 10^{5}N/m^{2} $
BETA
