Fluid Mechanics Viscosity Question 270

Options:

A) $ \rho ={\rho_{0}}\left[ 1-\frac{{\rho_{0}}gy}{B} \right] $

B) $ \rho ={\rho_{0}}\left[ 1+\frac{{\rho_{0}}gy}{B} \right] $

C) $ \rho ={\rho_{0}}\left[ 1+\frac{B}{{\rho_{0}}hgy} \right] $

D) $ \rho ={\rho_{0}}\left[ 1-\frac{B}{{\rho_{0}}hgy} \right] $

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Answer:

Correct Answer: B

Solution:

[b] Bulk modulus, $ B=-V_{0}\frac{\Delta p}{\Delta V}\Rightarrow \Delta V=-V_{0}\frac{\Delta p}{B} $ $ \Rightarrow ,V=V_{0}\left[ 1-\frac{\Delta p}{B} \right] $ $ \therefore ,Density,\rho ={\rho_{0}}{{\left[ 1-\frac{\Delta p}{B} \right]}^{-1}}={\rho_{0}}\left[ 1+\frac{\Delta p}{B} \right] $ where, $ \Delta \rho =\rho -{\rho_{0}}=h{\rho_{0}}g $ = pressure difference between depth and surface of ocean $ \therefore ,,\rho -{\rho_{0}}\left[ 1+\frac{{\rho_{0}}gy}{B} \right] $ (As h=y)