Fluid Mechanics Viscosity Question 273
Question: A homogeneous solid cylinder of length L ($ L<H/2 $ ), cross-sectional area $ A/5 $ is immersed such that it floats with its axis vertical at the liquid- liquid interface with length $ L/4 $ in the denser liquid as shown in the figure. The lower density liquid is open to atmosphere having pressure$ P_{0} $ . Then density D of solid is given by
Options:
A) $ \frac{5}{4}d $
B) $ \frac{d}{4} $
C) $ 4d $
D) $ \frac{d}{5} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Weight of cylinder = Upthrust due to upper liquid + Upthrust due to lower liquid. $ D\left( \frac{A}{5}\times L\times g \right)=d\left( \frac{A}{5} \right)\left( \frac{3}{4}L \right)g+2d\left( \frac{A}{5} \right)\left( \frac{L}{4} \right)\times g $ $ \therefore ,,D=\frac{5d}{4} $
BETA
