Fluid Mechanics Viscosity Question 283
Question: The cylindrical tube of a spray pump has radius, R, one end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :
Options:
A) $ \frac{VR^{2}}{nr^{2}} $
B) $ \frac{VR^{2}}{n^{3}r^{2}} $
C) $ \frac{V^{2}R}{nr} $
D) $ \frac{VR^{2}}{n^{2}r^{2}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Inflow rate of volume of the liquid = Outflow rate of volume of the liquid $ \pi R^{2}V=n\pi r^{2}(v)\Rightarrow v=\frac{\pi R^{2}V}{n\pi r^{2}}=\frac{VR^{2}}{nr^{2}} $
BETA
