Fluid Mechanics Viscosity Question 285
Question: For the arrangement shown in the figure, find the time interval in seconds after which the water jet ceases to cross the wall. Area of the cross section of the tank$ A=\sqrt{5}m^{2} $ and area of the orifice $ A=4cm^{2} $ . [Assume that the container remaining fixed]
Options:
A) $ 1000s $
B) $ 2000s $
C) $ 1500s $
D) $ 500s $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Let x be the height of the water level from The hole $ v=\sqrt{2gx}=\frac{\ell }{t}=\frac{1}{t} $ …(i) For vertical motion $ x=\frac{1}{2}gt^{2} $ ?(ii) Now solving (i) & (ii) we get $ \Rightarrow ,x=0.25m $ (i.e. level goes down from 0.81m to 0.25m.) Using equation of continuity $ \sqrt{5.,}\frac{dx}{dt}=\sqrt{2gx.}4\times {{10}^{-4}} $ On solving $ t=1000s $
BETA
