Fluid Mechanics Viscosity Question 286
Question: Air of density $ 1.2kg{{m}^{-3}} $ is blowing across the horizontal wings of an aero plane in such a way that its speeds above and below the wings are $ 150m{{s}^{-1}} $ and$ 100m{{s}^{-1}} $ , respectively. The pressure difference between the upper and lower sides of the wings, is
Options:
A) $ 60N{{m}^{-2}} $
B) $ 180,N{{m}^{-2}} $
C) $ 7500N{{m}^{-2}} $
D) $ 12500N{{m}^{-2}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Pressure difference $ P_{2}-P_{1}=\frac{1}{2}\rho (v_{2}^{2}-v_{1}^{2}) $ $ =\frac{1}{2}\times 1.2\left( {{(150)}^{2}}-{{(100)}^{2}} \right)=7500N{{m}^{-2}} $
BETA
