Fluid Mechanics Viscosity Question 291
Question: A square box of water has a small hole located in one of the bottom comer. When the box is fall and sitting on a level surface, complete opening of the whole results in a flow of water with a speed$ v_{0} $ , as shown in figure. When the box is half empty, it is tilted by $ 45{}^\circ $ so that the hole is at the lowest point. Now the water will flow out with a speed of
Options:
A) $ v_{0} $
B) $ v_{0}/2 $
C) $ v_{0}/\sqrt{2} $
D) $ v_{0}/\sqrt[4]{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ v_{0}=\sqrt{2gh}\Rightarrow v_{2}=\sqrt{2g\frac{h}{\sqrt{2}}}=\frac{v_{0}}{\sqrt[4]{2}} $
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