Fluid Mechanics Viscosity Question 315
Question: Drops of liquid of density p are floating half immersed in a liquid of density a. If the surface tension of liquid is T, the radius of the drop will be
Options:
A) $ \sqrt{\frac{3T}{g(3\rho -\sigma )}} $
B) $ \sqrt{\frac{6T}{g(2\rho -\sigma )}} $
C) $ \sqrt{\frac{3T}{g(2\rho -\sigma )}} $
D) $ \sqrt{\frac{3T}{g(4\rho -3\sigma )}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Balancing the forces acting on the drop, we get $ \frac{4}{3}\pi r^{3}\rho g=2\pi rT+\frac{1}{2}.\frac{4}{3}\pi r^{3}\sigma \Rightarrow r=\sqrt{\frac{3T}{(2\rho -\sigma )g}} $
BETA
