Fluid Mechanics Viscosity Question 336
Question: If work W is done in blowing a bubble of radius R from a soap solution, then the work done in blowing a bubble of radius 2R from the same solution is [MP PET 1990]
Options:
W/2
B)2W
4W
D)$ 2\frac{1}{3} $ W
Show Answer
Answer:
Correct Answer: C
Solution:
$ W=8\pi R^{2}T $ \ $ W\propto R^{2} $ (T is constant) If radius becomes double then work done will become four times.
BETA
