Fluid Mechanics Viscosity Question 345
Question: The amount of work done in forming a soap film of size $ 10,cm\times 10,cm $ is (Surface tension $ T=3\times {{10}^{-2}},N/m) $ [MP PET 1994; MP PET 2000]
Options:
A) $ 6\times {{10}^{-4}},J $
B)$ 3\times {{10}^{-4}},J $
C) $ 6\times {{10}^{-3}},J $
D)$ 3\times {{10}^{-4}},J $
Show Answer
Answer:
Correct Answer: A
Solution:
$ E=T\times \Delta A=3\times {{10}^{-2}}\times 2(100\times {{10}^{-4}})=6\times {{10}^{-4}}J $
BETA
