Fluid Mechanics Viscosity Question 356
Question: A mercury drop of radius 1cm is sprayed into $ 10^{6} $ drops of equal size. The energy expended in joules is (surface tension of Mercury is $ 460\times {{10}^{-3}}N/m) $ [EAMCET 2001]
Options:
A) 0.057
5.7
C) $ 5.7\times {{10}^{-4}} $
D) $ 5.7\times {{10}^{-6}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ W=T\Delta A=4\pi R^{2}T({{n}^{1/3}}-1) $ $ =4\times 3.14\times {{({{10}^{-2}})}^{2}}\times 460\times {{10}^{-3}}\times [{{(10^{6})}^{1/3}}-1] $ $ =0.057 $
BETA
