Fluid Mechanics Viscosity Question 67
If water rises in a capillary tube up to 3 cm. What is the diameter of capillary tube (Surface tension of water = 7.2×10² N/m ) [RPMT 2002]
Options:
A) $ 9.6\times 10^{4}m $
B)$ 9.6\times 10^{3}m $
C)$ 9.6\times 10^{2}m $
D)$ 9.6\times 10^{1}m $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \ h=\frac{2T\cos \theta }{rdg} $ , for water $ \theta =0{}^\circ $ Þ $ r=\frac{2T}{hdg}=\frac{2\times 7.2\times {{10}^{-2}}}{3\times {{10}^{-2}}\times 10^{3}\times 9.8}=4.8\times {{10}^{-4}} $ \ $ d=2r=9.6\times {{10}^{-4}},m $
BETA
