Gravitation Question 277
Question: A satellite moves in a circle around the earth. The radius of this circle is equal to one half of the radius of the moon’s orbit. The satellite completes one revolution in [J&K CET 2005]
Options:
A) $ [\frac{1}{2}] $ lunar month
B) $ [\frac{2}{3}] $ lunar month
C) $ [{{2}^{-3/2}}] $ lunar month
D) $ [{{2}^{3/2}}] $ lunar month
Show Answer
Answer:
Correct Answer: C
Solution:
Time period of revolution of moon around the earth= 1 lunar month. $ [\frac{T_{s}}{T_{m}}={{\left( \frac{r_{s}}{r_{m}} \right)}^{3/2}}={{\left( \frac{1}{2} \right)}^{3/2}}] $ Þ$ [T_{s}={{2}^{-3/2}}] $ lunar month.
BETA
