Gravitation Question 281
Question: The gravitational force between two stones of mass 1 kg each separated by a distance of 1 metre in vacuum is [DPMT 1984]
Options:
A) Zero
B)$ [6.675\times {{10}^{-5}},newton] $
C) $ [6.675\times {{10}^{-11}},newton] $
D)$ [6.675\times {{10}^{-8}},newton] $
Show Answer
Answer:
Correct Answer: C
Solution:
$ [F=G\frac{m_{1}m_{2}}{r^{2}}] $ $ [=6.675\times \frac{1\times 1}{1^{2}}\times {{10}^{-11}}=6.675\times {{10}^{-11}}N] $
BETA
