Gravitation Question 290
Question: Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to[Kerala PET 2005]
Options:
A)$ [R^{2}] $
B)$ [{{R}^{-2}}] $
C) $ [R^{4}] $
D)$ [{{R}^{-4}}] $
Show Answer
Answer:
Correct Answer: C
Solution:
$ [F=\frac{G\times m\times m}{{{(2R)}^{2}}}] $ =$ [\frac{G\times {{\left( \frac{4}{3}\pi R^{3}\rho\right)}^{2}}}{4R^{2}}] $ $ [=\frac{4}{9}{{\pi }^{2}}{{\rho }^{2}}R^{4}] $ \ $ [F\propto R^{4}] $
BETA
