SATHEE: Gravitation Question 2

Gravitation Question 2

Question: The time period of a simple pendulum on a freely moving artificial satellite is [CPMT 1984; AFMC 2002]

Options:

A) Zero

B) 2 sec

C) 3 sec

D) Infinite

Show Answer

Answer:

Correct Answer: D

Solution:

Time period of simple pendulum $ [T=2\pi \sqrt{\frac{l}{g’}}] $ In artificial satellite $ [g’=0] $ \ T = infinite.

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Gravitation Question 2

Question: The time period of a simple pendulum on a freely moving artificial satellite is [CPMT 1984; AFMC 2002]

Options:

Answer:

Solution:

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