Gravitation Question 336
The potential energy of a rock, having mass m and located at a height of$ [3.2\times 10^{6}m] $ from the earth surface, is
Options:
A) $ [-6,,mgR_{e}] $
B) $ [-0.67,,mgR_{e}] $
C) $ [-0.99,,mgR_{e}] $
D) $ [-0.33,,mgR_{e}] $
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Answer:
Correct Answer: B
Solution:
- Mass of the $ [rock=m] $ and height of rock from earth $ [\left( h \right)= R_{e}/2 =3.2\times 10^{6}m] $
We know that gravitational potential energy of the rock at a height
$ \[h=-\frac{GM_{e}m}{{R_{e}}+h}=-\frac{2}{3}mgR_{e}\] $
$ [\left( \text{where } GM_{e}= gR_{e}^{2} \text{ and } h = R_{e} \right)] $
BETA
