Gravitation Question 365
Question: The gravitational field due to a mass distribution is $ [E=K/x^{3}] $ in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is
Options:
A) $ [K/x] $
B) $ [K/2x] $
C) $ [K/x^{2}] $
D) $ [K/2x^{2}] $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ [V=-\int_{\infty }^{x}{Edx=}\int_{\infty }^{x}{K{{x}^{-3}}dx=\frac{K}{2x^{2}}}.] $ .
BETA
