Gravitation Question 366
Question: Infinite number of masses, each 1 kg are placed along the x-axis $ [at x=\pm1 m, \pm2m, \pm4m, \pm8m] $ $ [16m,\ldots ] $ the magnitude of the resultant gravitational potential in terms of gravitational constant G at the origin in $ [(x=0)] $ is
Options:
G/2
G
2G
4G
Show Answer
Answer:
Correct Answer: C
Solution:
$ [V=-\frac{GM}{r}=-G\left( \frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+….\infty\right)] $
$ \[=-G\left( \frac{1}{1-1/2} \right)=-2G\] $
BETA
