Gravitation Question 49
Question: The angular speed of earth, so that the object on equator may appear weightless, is $ [(g=10,m/s^{2}] $ , radius of earth 6400 km)[Pb. PMT 2001]
Options:
A) $ [1.25\times {{10}^{-3}}rad/sec] $
B) $ [1.56\times {{10}^{-3}}rad/sec] $
C) $ [1.25\times {{10}^{-1}}rad/sec] $
D) 1.56 rad/sec
Show Answer
Answer:
Correct Answer: A
Solution:
For condition of weightlessness of equator
$ [\omega =\sqrt{\frac{g}{R}}=\frac{1}{800}=1.25\times {{10}^{-3}}\frac{rad}{s}] $
BETA
