Gravitation Question 130
Question: A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface to a height $ [h=3R] $ . The change in gravitational potential energy of the body is [CBSE PMT 2002]
Options:
A) $ [\frac{2}{3}mgR] $
B) $ [\frac{3}{4}mgR] $
C) $ [\frac{mgR}{2}] $
D) $ [\frac{mgR}{4}] $
Show Answer
Answer:
Correct Answer: B
Solution:
$ [\Delta U=\frac{mgh}{1+\frac{h}{R}}=\frac{mg\times 3R}{1+\frac{3R}{R}}=\frac{3}{4}mgR] $
BETA
