Gravitation Question 148
Question: The escape velocity for the earth is 11.2 km/sec. The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be [MP PMT 1999; Pb. PMT 2002]
Options:
A) 112.0 km/s
B) 5.6 km/s
C) 280.0 km/s
D) 56.0 km/s
Show Answer
Answer:
Correct Answer: D
Solution:
Escape velocity $ [v=\sqrt{\frac{2,GM}{R}}\Rightarrow \frac{v_{p}}{v_{e}}=\sqrt{\frac{M_{p}}{M_{e}}\times \frac{R_{e}}{R_{p}}}] $ $ [\Rightarrow ,,v_{p}=5v_{e}=5\times 11.2=56,,km/s] $
BETA
