Gravitation Question 154
Question: The angular velocity of rotation of star (of mass M and radius R) at which the matter start to escape from its equator will be[MH CET 1999]
Options:
A) $ [\sqrt{\frac{2GM^{2}}{R}}] $
B) $ [\sqrt{\frac{2GM}{g}}] $
C) $ [\sqrt{\frac{2GM}{R^{3}}}] $
D) $ [\sqrt{\frac{2GR}{M}}] $
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Answer:
Correct Answer: C
Solution:
Escape velocity $ [v=\sqrt{\frac{2GM}{R}}] $
If star rotates with angular velocity w then
$ [\omega =\frac{v}{R}=\frac{1}{R}\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2GM}{R^{3}}}] $
BETA
