Gravitation Question 222
Question: A rectangular block of size $ [10cm\times 8cm\times 5cm] $ is kept in three different positions P, Q and R in turn as . In each case, the shaded area is rigidly fixed and a definite force F is applied tangentially to the opposite face to deform the block. The displacement of the upper face will be
Options:
A) Same in all the three cases
B)Maximum in $ [P] $ position
C)Maximum in $ [Q] $ position
D)Maximum in $ [R] $ position
Show Answer
Answer:
Correct Answer: D
Solution:
- $ [\eta =\frac{F/A}{x/L}\Rightarrow x=\frac{L}{\eta }\times \frac{F}{A}] $ In $ [\eta ] $ and F are constant, then $ [x\propto \frac{L}{A}] $ For maximum displacement, area at which force applied should be minimum and vertical side should be maximum. This is given in the R position of rectangular block.
BETA
