Kinematics Question 275
Question: A body, constrained to move in the Y-direction is subjected to a force given by $ \overrightarrow{F}=(-2\hat{i}+15\hat{j}+6\hat{k})N. $ What is the work done by this force in moving the body a distance 10 m along the Y-axis [CBSE PMT 1994]
Options:
A) 20 J
B) 150 J
C) 160 J
D) 190 J
Show Answer
Answer:
Correct Answer: B
Solution:
$ W=\vec{F}.\vec{r} $
$ =(-2\hat{i}+15\hat{j}+6\hat{k})(10\hat{j})=150 $
BETA
