Kinematics Question 281

The resultant of the two vectors having magnitude 2 and 3 is 1. What is their cross product

Options:

A) 6

B) 3

C) 1

D) 0

Show Answer

Answer:

Correct Answer: D

Solution:

$ \sqrt{2^{2}+3^{2}+2\times 2\times 3\times \cos \theta }=1 $

By solving we get $ \theta =180{}^\circ $ \quad $ \vec{A}\times \vec{B}=0 $



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