Kinematics Question 288
In an clockwise system [CPMT 1990]
Options:
A) $ 30{}^\circ $
B) $ 45{}^\circ $
C) $ 60{}^\circ $
D) $ 90{}^\circ $
Show Answer
Answer:
Correct Answer: B
Solution:
$ |\vec{A}\times \vec{B}|=|\vec{A}||\vec{B}|\sin\theta$ therefore $ AB\sin \theta = AB\cos \theta $ therefore $ \tan \theta =1 $
$ \theta =45{}^\circ $
 BETA
  BETA 
             
             
           
           
           
          