Kinematics Question 288
Question: In an clockw it’se system [CPMT 1990]
Options:
A) $ 30{}^\circ $
B) $ 45{}^\circ $
C) $ 60{}^\circ $
D) $ 90{}^\circ $
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Answer:
Correct Answer: B
Solution:
$ |\vec{A}\times \vec{B}|=\vec{A}.\vec{B} $ therefore $ AB\sin \theta =AB\cos \theta $ therefore $ \tan \theta =1 $
$ \theta =45{}^\circ $