Kinematics Question 29
Question: A person goes 10 km north and 20 km east. What will be displacement from initial point [AFMC 1994, 2003]
Options:
A) 22.36 km
B) 2 km
C) 5 km
D) 20 km
Show Answer
Answer:
Correct Answer: A
Solution:
$ \overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC} $
$ AC=\sqrt{{{(AB)}^{2}}+{{(BC)}^{2}}} $
$ =\sqrt{{{(10)}^{2}}+{{(20)}^{2}}} $
$ =\sqrt{100+400} $
$ =\sqrt{500} $
$ =22.36km $
BETA
