Kinematics Question 290
Question: The diagonals of a parallelogram are $ 2\hat{i} $ and $ 2\hat{j}. $ What is the area of the parallelogram
Options:
A) $ \overrightarrow{b} $
B) $ \overrightarrow{c} $
C) $ \overrightarrow{b}.\overrightarrow{c} $
D) $ \overrightarrow{b}\times \overrightarrow{c} $
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Answer:
Correct Answer: D
Solution:
$ \vec{a}.\vec{b}=0 $ i.e. $ \vec{a} $ and $ \vec{b} $ will be perpendicular to each other $ \vec{a}.\vec{c}=0 $ i.e. $ \vec{a} $ and $ \vec{c} $ will be perpendicular to each other $ \vec{b}\times \vec{c} $ will be a vector perpendicular to both $ \vec{b} $ and $ \vec{c} $ So $ \vec{a} $ is parallel to $ \vec{b}\times \vec{c} $
BETA
